Bonjour,
J’écris un livre sur les maths, donc beaucoup de figures faites avec tkz.
Tout se passait bien. Or mon éditeur me demande des modifications.
Beaucoup de figures ne passent plus depuis la mise à jour de ma TeX Live ; le package qui pose problème est apparemment tkz-euclide.
J’ai trouvé certains changements concernant le cercle:
on ne fait plus \tkzDrawCircle : dans certains cas il faut passer d’abord par
\tkzDefCircle et \tkzGetPoint.
Dans l’exemple suivant, je ne sais pas où cela coince. Merci pour une aide.
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\documentclass[a4,DIV=18]{scrartcl}
\usepackage{tkz-tab,tkz-fct}%,tkz-tukey}
\usepackage{xkeyval,ifthen}
\usepackage{tkz-euclide}
\usetikzlibrary{babel,arrows,shadows,decorations.pathmorphing,patterns,calc}
\usepackage{amsfonts,bbm,mathrsfs,amsmath,amssymb,amsthm}%,tkz-bbpage}
\usepackage[utf8]{inputenc}
\usepackage[upright]{fourier}
\usepackage[greek,french]{babel}
%\usepackage[usenames,dvipsnames,svgnames]{xcolor}
\usepackage{scratch}
\usepackage{tabularx,colortbl,xcolor}
\usepackage{multicol,url,pifont}
\setlength{\columnseprule}{.2pt}
\unitlength=1cm
\renewcommand\FrenchLabelItem{\textbullet}
\renewcommand{\arraystretch}{1.3}
\begin{document}
\begin{center}
%\begin{figure}[!h]
%\centering
\begin{tikzpicture}[scale=.7]
\clip(-.5,-.6) rectangle (13,4.5);
\tkzInit[xmin=0,xmax=7,ymin=0,ymax=4]
\tkzFctPar[id=fct1,domain=0:pi]{2*(t-sin(t))}{2*(1-cos(t))}
\tkzDefPoint(2pi,0){B} \tkzDefPoint(2pi,4){C} \tkzDefPoint(0,0){A}
\tkzDefMidPoint(A,B) \tkzGetPoint{O} \tkzDefMidPoint(B,C) \tkzGetPoint{D}
\tkzDefMidPoint(A,C) \tkzGetPoint{E}
\tkzDefPoint(pi-2,2){F}
\tkzDefPoint(1.8,0){N} \tkzDefPoint(2*pi-1.8,0){P}
\tkzDefPoint(1.8,2){En} \tkzDefPoint(2*pi-1.8,2){Ep}
\tkzDefPoint(2*((.9)-sin(.9)),2*(1-cos(.9))){K}
\tkzDefPoint(2*(pi-.9-sin(pi-.9)),2*(1-cos(pi-.9))){G}
\tkzDefLineparallel=through K \tkzGetPoint{K’}
\tkzInterLL(B,C)(K,K’) \tkzGetPoint{M}
\tkzDefLineparallel=through G \tkzGetPoint{G’}
\tkzInterLL(B,C)(G,G’) \tkzGetPoint{I}
\tkzInterLL(K,M)(A,C) \tkzGetPoint{L}
\tkzDefPointByprojection=onto A–B{V}% \tkzGetPoint{V}
\tkzInterLL(G,I)(A,C) \tkzGetPoint{H}
%\tkzDrawSegments[dashed](P,Ep N,En)
\tkzDrawSegments(A,B B,C A,C F,D)
\tkzLabelPointsbelow
\tkzLabelPointsright
\tkzLabelPointsabove
%\tkzLabelPointabove{$E_n$}\tkzLabelPointabove{$E_p$}
%\tkzDrawArcdashed(P)
\tkzInterLL(En,N)(K,M) \tkzGetPoint{Y}
\tkzLabelPointsabove left
%\tkzLabelPointsleft
%\tkzLabelPointsabove right
%\tkzDrawPoints(A,B,C,D,E,F,N,P,K,G,M,O,I,L,V,Ep,En,Y)
\begin{scope}[shift={(10cm,2cm)},rotate=-90]
\tkzInit[xmin=-2,xmax=2,ymin=0,ymax=4]
\tkzDefPoint(0,0){e} \tkzDefPoint(0,-2){a} \tkzDefPoint(0,2){b}
\tkzDefCircle(e,a)
\tkzDefPoint(0:2){o}
\tkzDefPoint((-90)+((180*.9)/pi):2){n}
\tkzDefPointByreflection=over e–o \tkzGetPoint{p}
\tkzDefPointBysymmetry=center e \tkzGetPoint{p’}
\tkzDefPointBysymmetry=center e \tkzGetPoint{n’}
\tkzDefPointByprojection=onto p–p’ \tkzGetPoint{x}
\tkzDefPointByprojection=onto n–e \tkzGetPoint{y}
%\tkzDefPointBysymmetry=center x \tkzGetPoint{z}
\tkzDrawPoints(e,a,b,n,p,o)
\tkzDrawSegments(p,p’ a,b n,e)
\begin{scope}
%\tkzDrawSegmentline width=1.5pt
\tkzDrawSegmentdashed,line width=1.5pt
\tkzDrawCircleline width=1.5pt
\end{scope}
\tkzLabelPointsright
\tkzLabelPointsleft
\tkzLabelPointsbelow right
%\tkzLabelPointsright
\tkzLabelPointsbelow
%\tkzLabelPointsabove left
\tkzLabelPointsabove
%\tkzMarkRightAngle(a,x,e)
%\tkzMarkRightAngle(e,y,a)
\end{scope}
\begin{scope}
%\tkzDrawSegmentsline width=1.5pt
\tkzDrawSegmentsdashed,line width=1.5pt
\tkzDrawCircleline width=1.5pt
\end{scope}
\end{tikzpicture}
%\caption{Le point $o$ de la roulette se trouve en $O$}\label{oO}
%\end{figure}
\end{center}
\end{document} %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%